Assuming this may be MySQL, use a mysql_fetch_object like: $result=mysql_query($sql); $r=mysql_fetch_object($result); echo $r->real_name; Other databases have similar syntax. Hope this helps, Ron Patterson USA.NET "Rankin, Randy" <[EMAIL PROTECTED]> wrote: > All: > > I am new to PHP and was hoping for some input to what is probably an 'easy' > question. > > The following SQL statement returns 1 row: > > $sql = "SELECT id, real_name FROM authorization WHERE username='$username' > and password='$password'"; > > All I want to do is assign the results of the field real_name to a variable > called $salesperson, but I cannot seem to get it to work. > > Thanks inadvance for your help, > > Randy Rankin > > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > To contact the list administrators, e-mail: [EMAIL PROTECTED] > ____________________________________________________________________ Get free email and a permanent address at http://www.netaddress.com/?N=1 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
