1.  safe to assume that there is a column named "nombre"?
2.  try using index numbers instead, i.e;, instead of $myrow("nombre"),
try $myrow(1)...


Fernando Gonzalez wrote:
> 
> Thanks, but it wont work.
> I have eliminate the space but still the same message.
> I have realized that the problem is below that line:
> the problem is pointing to the line where i fetch the first variable:
> $nombre=$myrow("nombre");
> 


-- 
Leo G. Divinagracia III
[EMAIL PROTECTED]

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