Not possible.

do this $result_1 = mysql_query($sql1) or die('Insert 1 failed');
do this $result_2 = mysql_query($sql2) or die('Insert 2 failed');


-----Original Message-----
From: Steve Fitzgerald [mailto:[EMAIL PROTECTED]]

I'm trying to insert data into two separate tables using 1 INSERT. The code
below represents a first crack at it, but I can't seem to figure out how to
get this to work properly.



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