"Ron Gallant" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I am querying a list with a date field. I want to order the list by the
> date field and only show each days date once with the other fields
showing.
>
> (row 1) 2001-08-19 - some text here.
> (row 2) more text under same date. My date does
not
> show.
> (row 3) 2001-08-20 - Lots of text today.
> (row 4) Even more text here today. My date does
not
> show.
> (row 5) Yes more text, date not showing.
This seems to be a recurrent question in various guises;
The idea is simple: sort by date (so all equal dates are together),
then keep a temporary variable set to the last-seen date. When the
date changes, output a new date value.
========== example.php ============
<?php
mysql_connect("host", "user", "pwd")
or die("Error connecting: ".mysql_error());
// return the 20 most recent items
$query =
"SELECT mydate,mytext "
."FROM table "
."ORDER BY mydate DESC "
."LIMIT 20";
$result = mysql_db_query("dbase", $query)
or die("Error querying: ".mysql_error());
// show results in a table
$lastdate = "";
echo "\n<table>";
while ($row = mysql_fetch_array($result)) {
extract($row);
if ($lastdate == $mydate)
$t = "";
else
$t = $lastdate = $mydate;
echo "\n\t<tr><td>$t</td><td>$mytext</td></tr>";
}
echo "\n<\table>";
?>
===============================
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