I suppose you could just remove the $ and/or the comma with a regexp...
www.php.net/eregi_replace

-- David Balatero
----- Original Message -----
From: "Rick Eicher II" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, September 14, 2001 3:00 PM
Subject: [PHP-DB] currency out of postgresql


> After I do the add $money comes out to be 0. The data comes out as $0 and
> $5,217.00, I need to add these two to get $5,217.00. How do you add money
> with the dollor sign in the data?
>
> rick
>
> -----Original Message-----
> From: Bas Jobsen [mailto:[EMAIL PROTECTED]]
> Sent: Friday, September 14, 2001 7:24 AM
> To: Rick Eicher II
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] currency out of postgresql
>
>
> > $formatted = sprintf("%01.2f", $money);
> > printf ("<td align=\"center\">%01.2f</td></tr>\n", $formatted);
>
> maybe twice, try:
> $formatted = sprintf("%01.2f", $money);
> echo "<td align=\"center\">$formatted</td></tr>\n";
>
>
> ----- Original Message -----
> From: "Rick Eicher II" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Friday, September 14, 2001 6:48 PM
> Subject: [PHP-DB] currency out of postgresql
>
>
> > I am trying to get two currency values from out of the database, add
them
> > together and print the to the screen. I am using the following code.
> >
> > $money = $myrow[6] + $myrow[7];
> > $formatted = sprintf("%01.2f", $money);
> > printf ("<td align=\"center\">%01.2f</td></tr>\n", $formatted);
> >
> > $myrow[] is the array that I load the database records into.
> >
> > I can echo $myrow[6] & $myrow[7], which will show like $4.00 and
$4000.00.
> > But when I add them together the come out as 0 every time. The columns
in
> > the database are of type money. This is a postgresql database.
> >
> > Does any one see the errors of my ways?
> >
> > thanks,
> > Rick Eicher II
> > www.pbol.net
> >
> >
> > --
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>
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