please show the REAL output from your query and what it should REALLY look
like

-----Original Message-----
From: Bas Jobsen [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 02, 2001 3:38 PM
To: Rick Emery; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Howto make a double LEFT JOIN


> SELECT table1.id FROM table1 LEFT JOIN table2 ON table1.id=table2.id LEFT
> JOIN table3 ON table2.id=table3.id

Well, oke now i have:
table1:
id|no
1|1
2|1

table2:
id|no
1|1
1||1

table2:
id|no
1|1
1||1
1||1

The result i want tot have is:
id|sum(table2.no)|sum(table3.no)|
1|2|3
2|0|0
my query:

SELECT DISTINT( table1.id) AS test, SUM(table2.no) AS tot, SUM(table3.no
FROM table1 LEFT JOIN table2 ON table1.id=table2.id LEFT JOIN table3 ON
table2.id=table3.id GROUP BY test ORDER BY tot DESC

which give my something like:
id|5|5|
1|2|3
2|0|0
:(






----- Original Message -----
From: "Rick Emery" <[EMAIL PROTECTED]>
To: "'Bas Jobsen'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, October 02, 2001 10:19 PM
Subject: RE: [PHP-DB] Howto make a double LEFT JOIN


> SELECT table1.id FROM table1 LEFT JOIN table2 ON table1.id=table2.id LEFT
> JOIN table3 ON table2.id=table3.id
>
> -----Original Message-----
> From: Bas Jobsen [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, October 02, 2001 3:13 PM
> To: Rick Emery; [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] Howto make a double LEFT JOIN
>
>
> > Remove the parentheses
> > SELECT table1.id FROM table1 LEFT JOIN table2 LEFT JOIN table3 ON
> > table2.id=table3.id ON table1.id=table2.id
>
> I still got:
> MySQL retourneerde: You have an error in your SQL syntax near 'LEFT JOIN
> table3 ON
> table2.id=table3.id ON table1.id=table2.id' at line 1
>
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