Change code as follows: <? $msgcre = "SELECT msg FROM creators WHERE id='0'"; $result = mysql_query($msgcre); $row = mysql_fetch_array($result); echo "<FONT color='#000000' style='font-size: 10pt; font-weight: bold'>".$row['msg']."</font>"; ?>
-----Original Message----- From: Andrew Duck [mailto:[EMAIL PROTECTED]] Sent: Sunday, October 28, 2001 7:00 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Resource id #2 I am trying to select a message from a table in a database. the message will will be in column 'msg' and will be in same row as id='0'. I need that msg put to the screen. With the code below I get the error: Resource id #2 Can someone please explain how I can fix this.. Thankyou in advance. <? $msgcre = "SELECT msg FROM creators WHERE id='0'"; $msg = mysql_query($msgcre); echo "<FONT color='#000000' style='font-size: 10pt; font-weight: bold'>$msg</font>"; ?> -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
