A quick rewrite of your code:
<?php
$conn = mysql_connect($host, $user, $pass);
if (!$conn) {
echo 'Could not connect: '. mysql_error();
exit;
}
mysql_select_db($dbname);
$sql = "SELECT * FROM members";
$result = mysql_query($sql);
if (!$result) {
echo 'Could not run Query: '. mysql_error();
exit;
}
while ($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
extract($row);
print "$ircname, $email, $realname, $asl, $info <br>";
}
?>
Your question was how to print the query, in this case you'd just print
$sql. That was the point of the above but I got a bit carried away :) Oh,
mysql_error() can be very useful for debugging. Regarding the type
resource, have a look here:
http://www.php.net/manual/en/language.types.resource.php
Regards,
Philip Olson
On Fri, 4 Jan 2002, louie miranda wrote:
> Hi, is it possible to print the sql query? i mean
> i want to print the output of the command "SELECT * FROM members;"
> and output it into html, i tried
>
> print $result; -- it gives me different output..
>
> > Resource id #2
>
>
> ty,
> louie...
>
> # PHP SCRIPT ###############################################
>
> <html>
> <body>
>
> <?php
>
> $db = mysql_connect("my_db_host", "my_db_user", "my_db_pass")
> or die("Could not connect");
>
> mysql_select_db("cavite",$db);
>
> $result = mysql_query("SELECT * FROM members",$db) or
> die("Error:".mysql_error()
> );
>
> printf("ircname: %s<br>", mysql_result($result,0,"ircname"));
> printf("email: %s<br>", mysql_result($result,0,"email"));
> printf("realname: %s<br>", mysql_result($result,0,"realname"));
> printf("asl: %s<br>", mysql_result($result,0,"asl"));
> printf("info: %s<br>", mysql_result($result,0,"info"));
>
> print "<br><br>";
>
> ?>
>
> </body>
>
> </html>
>
> # PHP SCRIPT ###############################################
>
>
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