I don't know for sure if this works, but you may try simply adding a line with
the name of the variable in the PHP code.
For example, this works - I don't know, however, if it works with multiple
$lala "It works!"; // echoes "It works!"
Keith Posehn wrote:
> Quick question for you guru's out there:
> I have a set of dynamic pages. In the mysql database, I have most of my
> content stored and retrieve it with queries sent from php. Is there a way to
> have php send the query, get the data which _includes_ php code in it, and
> then process the code from the query as if it were a normal php code, before
> going on?
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