Hi there :)

What happens when you change this line ($query = "select * from auth where
password = ".$password."";
)

to this: (no periods)

$query = "select * from auth where password = '$password'";

Cheers, Joe :)



"Greg Lobring" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I dont understand why this is causing me so much trouble, hopefully
someone
> can help. I have a simple PHP script that takes the user id and password
> from a form on a page...here is the php used after submitting the form:
>
> <?
> @ $db = mysql_pconnect("localhost", "blah", "blah");
> if (!$db)
> {
> echo "Error: Could not connect to database.";
> exit;
> }
> mysql_select_db("blahblah");
> $query = "select * from auth where password = ".$password."";
> $result = mysql_query($query);
> $num_results = mysql_num_rows($result);
> echo "Number of Rows: ".$num_results."";
> mysql_close($db);
> ?>
>
> It connects fine, and when the query returns NO (0) rows, it appears
> correct. However, when the query returns a record, I get the following
> error:
>
>
> Warning: Supplied argument is not a valid MySQL result resource in
picks.php
> on line 16
>
> Where line 16 is the the line that says $num_results =
> mysql_num_rows($result);
>
>
> Does anyone have any advice?
>
> Appreciated in advance..
>
> Greg
>
>
>
> _________________________________________________________________
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>



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