$query="query"; $result=mysql_query($query); $pd=mysql_result($result);
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Notice the zig-zag - $query is first on the left side, then on the right side, then $result is first on the left side, then on the right side. Bogdan Ryan Snow wrote: >Hi, Im kinda new to this list. Can anyone tell me what is the proper way >to interpolate my php variables into my mysql queries? > >I've been trying $query = "SELECT password FROM users WHERE login='$login'"; > > >then: > mysql_query($result); > $pd = mysql_result($result); > >but I get a message that says: "Supplied Argument is not a valid >MySQL-Link resource" > >any ideas, anyone? > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
