The info is not full but I'll try to help. Lets say the name of the field in the two 
tables is common_field.
Then we do
SELECT all_that_is_needed FROM table1,table2 WHERE 
table1.common_field=table2.common_field;
And an optimized variant:
SELECT all_that_is_needed FROM table1 LEFT JOIN table2 USING(common_field);
If in the two tables we have two columns with equal data but with different names then 
we do:
SELECT all_that_is_needed FROM table1 LEFT JOIN table2 ON 
table1.common_field_name_table1=table2.common_field_name_table2;
So 
SELECT all_that_is_needed FROM table1 LEFT JOIN table2 USING(common_field);
is equal to:
SELECT all_that_is_needed FROM table1 LEFT JOIN table2 ON 
table1.common_field=table2.common_field;

Hope that is clear.

Best regards,
Andrey

----- Original Message ----- 
From: "Ron" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, March 21, 2002 3:32 PM
Subject: [PHP-DB] Relational database


> I am trying to get fields from 2 different tables that have the same field
> name to pull the records from one table
> For example
> mysql_connect($DBhost,$DBuser,$DBpass) or die("Unable toconnect to
> database");
> @mysql_select_db("$DBName") or die("Unable to select database $DBName");
> $sqlquery1 = mysql_query("SELECT Description, Impact, Isolation" .
> "FROM ccsd, log WHERE ccsd=log.logccsd");
> 
> while ($query = mysql_fetch_array($sqlquery1)) {
>  $CCSD = $query["CCSD"];
>  $Description = $query["Description"];
>  $Impact = $query["Impact"];
>  $Isolation = $query["Isolation"];
> }
> This code is not working.....help please.........yes I am a newbie!
> 
> 
> 
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> 
> 


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