Ok I made the changes you suggested and unfortunately I am getting the same results... Could not execute query, I manually put entries into the tables so that the update command would just overwrite the current contents. Here is my code this far, I think my problem (correct me if I am wrong) lies in the fact that each of select boxes does not contain a unique name, needless to say I am stuck: <?php $dir_name = "/path/to/images/directory/"; $dir = opendir($dir_name); $file_list .= "<p><FORM METHOD=\"post\" ACTION=\"index_done.php3\"> <SELECT NAME=\"files\">"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name !="..")) { $file_list .= "<OPTION VALUE=\"$file_name\" NAME=\"$file_name\">$file_name</OPTION>"; } } $file_list .= "</SELECT><br><br><INPUT TYPE=\"submit\" NAME=\"submit\" VALUE=\"select\"></FORM></p>"; closedir($dir); ?> Select boxes are filled with files from specified folder... then echoed to screen <? echo "$file_list"; ?> Working fine... when user click on image using said select box it links to this file, code is as follows: <?php $db_name = "db_name"; $table_name = "cm_index"; $connection = @mysql_connect("localhost", "user_name", "password") or die ("Could not connect to database. Please try again later."); $db = @mysql_select_db("$db_name",$connection) or die ("Could not select database table. Please try again later."); $sql = "UPDATE $table_name SET file_name=\"$files\""; $result = @mysql_query($sql, $connection) or die ("Could not execute query. Please try again later."); ?> Still getting could not execute query... sorry about not knowing where I am going wrong but still new to these advanced functions. Thanks in advance, Jas
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