Newbie question that maybe should belong in a mysql group, but how and why
does a varchar fragment a dbase?

//Micke
"Remco Oosten" <[EMAIL PROTECTED]> skrev i meddelandet
003c01c1ded7$72877760$[EMAIL PROTECTED]">news:003c01c1ded7$72877760$[EMAIL PROTECTED]...
> I don't think you can use text(50),
>
> It should be one of the following tinytext, mediumtext or text
> Or you should use char(50).
>
> I would try to avoid using varchar() it fragments the database.
>
> Remco
>
> ----- Original Message -----
> From: "Lisi" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Monday, April 08, 2002 11:11 AM
> Subject: [PHP-DB] Error creating new table
>
>
> > I am trying to create the following table using PHPMyAdmin:
> >
> > CREATE TABLE IF NOT EXISTS ayny(
> >          organization varchar(50) NOT NULL,
> >          subtitle varchar(50) NOT NULL,
> >          img varchar(20) NOT NULL,
> >          width varchar(5),
> >          height varchar(5),
> >          link varchar(30) NOT NULL,
> >          maintext text(50) NOT NULL,
> >          boxtext text(50) NOT NULL,
> >          ID INT(9) NOT NULL AUTO_INCREMENT,
> >          PRIMARY KEY(ID)
> > );
> >
> > But I keep getting the following error:
> >
> > MySQL said: You have an error in your SQL syntax near '(50) NOT NULL,
> > boxtext text(50) NOT NULL, ID INT(9) NOT NULL AUTO_INCREMENT,' at line 8
> >
> > Any ideas what I'\m doing wrong?
> >
> > TIA,
> >
> > -Lisi
> >
> >
> > --
> > PHP Database Mailing List (http://www.php.net/)
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> >
>



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