One thing I noticed quickly. You have too many opening ( on the line that
says:
while (($row = mysql_fetch_array($result, MYSQL_ASSOC))
3 opening and 2 closing.
This would cause a parse error. Without knowing which line is line 11, it is
hard to say if there is anything else.
HTH
MB
Chris Grigor <[EMAIL PROTECTED]> said:
> Howdi guys
>
> any help on this would be greatful
>
> I have a page that submits to this script with a value of search
>
> but when I submit it gives me an error Parse error: parse error
in /var/www/html/ul/mysql_fetch_array.php on line 11
> anyhelp here would be greatful, I dont see what the error could be
>
> Thanks
>
> Chris
>
>
> <?php
>
> mysql_connect("localhost", "username", "password") or
> die("couldnt connect");
> mysql_select_db("call_manage");
>
> $query = "SELECT company_name, ticket_id, date from log_request
where company_name like '%$search%'";
> $result = mysql_query($query);
>
> while (($row = mysql_fetch_array($result, MYSQL_ASSOC))
> printf ("Company: %s Ticket id: %s Date: %s", $row
["company_name"], $row["ticket_id"], $row["date"]);
>
> mysql_free_result($result);
> ?>
>
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