Hi Peter, Just a shot in the dark, but make sure that everything is correct case-sensitive wise. I know this has caused me grief in the past.
J. Wharton "Peter Roescher" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED]... > I have a mysql query like this > > SELECT * FROM personen WERE Id != '1' ORDER BY Bijnaam > > but it wont work > Supplied argument is not a valid MySQL result resource > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php