you need a second REQUIRED parameter:
mysql_result
(PHP 3, PHP 4 )
mysql_result -- Get result data
Description
mixed mysql_result ( resource result, int
row [, mixed field])
as copied from php's doc site...
http://www.php.net/manual/en/function.mysql-result.php
Manoj Japher wrote:
> hi,
> I have started working with PHP-MySQL recently. I have been
> getting a
> warning message which i am not able to debug. Could some one pls
> help
> me out?
>
> The message is
> Warning: mysql_num_rows(): supplied argument is not a valid
> MySQL
> result resource in /usr/local/apache2/htdocs/verify.php on line
> 37
>
> The code is
>
> @$db=mysql_pconnect("localhost:/var/lib/mysql/mysql.sock","","");
>
>
> if(!$db)
> {
> echo " The Server is Busy. Please Try Later ";
> exit;
> }
>
> mysql_select_db("userinfo");
>
> $query = "select * from userinfo";
>
> $mysql_results = mysql_query($query,$db);
>
> line 37:$num_result = mysql_num_rows($mysql_results);
>
> if($num_result == 0)
> {
> echo "<P>Invalid Username or Password entered</P>";
> exit;
> }
>
> Regards,
>
> Manoj
>
> 'I have miles to go before I sleep, and promises to keep'
>
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