Perhaps , $action  is not equal to "test".  Try initializing the $action
variable - instead of leaving it uninitialized.
$action = "test";

    echo "Test";

-----Original Message-----
From: Michel Bakkenes - <[EMAIL PROTECTED]>
Date: Friday, October 18, 2002 6:26 AM
Subject: [PHP-DB] Variable won't be passed from HTTP address bar

>Ok.. I'm not a newbie I thought.. I do have experience with PHP, but I
>never suffered from this error.
>I used on my own redhat 8.0 server the following test-script:
>if($action=="test"){ echo "Test";}
>I tried it to run with:
>It doesn't print anything. (which means I even can't print hello world
>Oh, other variable constructions like $bla = "blah" . echo $bla etc. do
>With regards,
>Michel Bakkenes
>J2ee developer
>Infolook BV
>Zevenbergen, The Netherlands

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