$query = ( " SHOW COLUMNS FROM user ");

$result =  mysql_query ( $query ) or die( mysql_error () );

while ( $row = mysql_fetch_array ($result) ){

$x = 0 ;

echo $row[$x] ;

$x++ ;

I would like to replace the table name "user" with a variable $table, that
wil automatically take the value of the selected table. I have tried many
times but cannot get the correct sql syntax, it keeps saying
"you have an error in your sql syntax near 'user' line 1" when i try it with
any ideas??

dave rice ([EMAIL PROTECTED])

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