Peter Beckman wrote:

Peter,
Thanks for your prompt reply.

Gonna need some additional information, such as:

 1. The first three rows your query returns
 2. The expected output
 3. The actual problem and/or error.
What I'm trying todo is build a radio box form
for the selection of ledger accounts for a account app.
( http://mustardandrelish.com/ledger)

Query returns (from HTML table):
<input type="radio" name="gl_acct" value=acct[]">
<input type="radio" name="gl_acct" value=acct[]">
<input type="radio" name="gl_acct" value=acct[]">

Expected results might be:

<input type="radio" name="gl_acct" value="1000" ">
<input type="radio" name="gl_acct" value="2000" ">
<input type="radio" name="gl_acct" value="3000" ">

And then "gl_acct" will be passed to the G/L entry screen
(sticky forms?)

TIA,
David


Peter

On Sun, 3 Nov 2002, David Jackson wrote:


Howdy --
How do I dynamically generate the "value" for radio buttons off the DB
(MySQL) backend? Here's some code that almost works

TIA,
David

--------------------- Almost works ----------------------------
<?php
$header = mysql_query ("SELECT * FROM chart
           ORDER BY acct ");

if ($row = mysql_fetch_array($header)) {
        do {
        print("<tr  bgcolor=\"white\" >");
   print '<td width="5"><input type="radio" name="gl_acct"
value=acct[]"></td>';
   print("<td width=\"12\">");
   print $row["acct"];
        print "</td><td width=\"12\">";
   print $row["cat"];
        print "</td><td >";
   print $row["descript"];
   print("</td></tr>\n");
               } while($row = mysql_fetch_array($header));

            } else {print "Sorry, no records were found!";}


?>


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Peter Beckman            Systems Engineer, Fairfax Cable Access Corporation
[EMAIL PROTECTED]                             http://www.purplecow.com/
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