Peter Beckman wrote:
Peter,
Thanks for your prompt reply.
Gonna need some additional information, such as:
1. The first three rows your query returns
2. The expected output
3. The actual problem and/or error.
What I'm trying todo is build a radio box form
for the selection of ledger accounts for a account app.
( http://mustardandrelish.com/ledger)
Query returns (from HTML table):
<input type="radio" name="gl_acct" value=acct[]">
<input type="radio" name="gl_acct" value=acct[]">
<input type="radio" name="gl_acct" value=acct[]">
Expected results might be:
<input type="radio" name="gl_acct" value="1000" ">
<input type="radio" name="gl_acct" value="2000" ">
<input type="radio" name="gl_acct" value="3000" ">
And then "gl_acct" will be passed to the G/L entry screen
(sticky forms?)
TIA,
David
Peter
On Sun, 3 Nov 2002, David Jackson wrote:
Howdy --
How do I dynamically generate the "value" for radio buttons off the DB
(MySQL) backend? Here's some code that almost works
TIA,
David
--------------------- Almost works ----------------------------
<?php
$header = mysql_query ("SELECT * FROM chart
ORDER BY acct ");
if ($row = mysql_fetch_array($header)) {
do {
print("<tr bgcolor=\"white\" >");
print '<td width="5"><input type="radio" name="gl_acct"
value=acct[]"></td>';
print("<td width=\"12\">");
print $row["acct"];
print "</td><td width=\"12\">";
print $row["cat"];
print "</td><td >";
print $row["descript"];
print("</td></tr>\n");
} while($row = mysql_fetch_array($header));
} else {print "Sorry, no records were found!";}
?>
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Peter Beckman Systems Engineer, Fairfax Cable Access Corporation
[EMAIL PROTECTED] http://www.purplecow.com/
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