You should write:

$myquery = "SELECT * FROM user WHERE username = '{$user}' ..." ;

As a bonus, it is much more readable.

Ignatius
____________________________________________
----- Original Message -----
From: "David" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, December 16, 2002 2:16 AM
Subject: [PHP-DB] Get error message, need help


> Hello all,
>
> I am new to PHP so I am going to need some help.
>
> I am trying to create a admin login page. But I am getting this error
> message:
>
> Parse error: parse error, unexpected T_VARIABLE in c:\program files\apache
> group\apache\htdocs\sunwestsilver\admin\tmpi5pcf76sy9.php on line 43
>
> tmpi5pcf76sy9.php is generated by Dreamweaver MX as a temp file from
> admin.php
>
> It is coming  from this line:
>
> this is line 43 code
>
> # $myquery = .'" AND password = '" . crypt($password, "xpz8ty") . "'";
>
> The complete code is:
>
>     // Query Database with username and encrypted password
>   #$myquery = "SELECT * FROM user WHERE username = '" . $user
>   #$myquery = .'" AND password = '" . crypt($password, "xpz8ty") . "'";
>   #$result = mysql_query($myquery);
>   #if (!$result)
>   #{
>   #  $error = "Cannot run Query";
>  #return($error);
>   #}
>
> Any help will be nice.
>
> I got this code from Dreamweaver MX: PHP Web Development pg. 257
>
> Thanks
>
> David
>
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
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>
>


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