MySQL cannot find the username in its grant tables. The error message very clearly states that there is no user named 'x,@host' which is the value of your $user variable. For your example, $email == 'x' and $femail == '@host'. The comma is included because it is part of the literal string, i.e., inside the double quotes.
hth, Doug On Tue, 14 Jan 2003 22:08:11 -0600, Addison Ellis wrote: >hello, > do you have any idea why the following(line 106)would return >the following >error message ? the login.php has an included form to create an >account and that is what will not connect. > >$connection = mysql_connect($host, $user,$password) //this is line 106 > >Warning: Access denied for user: 'x,@host' (Using password: YES) in >/users/infoserv/web/register/login.php on line 106 > >Warning: MySQL Connection Failed: Access denied for user: 'x,@host' >(Using password: YES) in /users/infoserv/web/register/login.php on >line 106 >Couldn't connect to server. > >my required file is as follows: ><? > $user="$email,$femail"; > $host="$hostname"; > $password="password('$password'),password('$fpassword')"; > $database="$classes"; >?> > > >thank you again for your time. addison >-- >Addison Ellis >small independent publishing co. >114 B 29th Avenue North >Nashville, TN 37203 >(615) 321-1791 >[EMAIL PROTECTED] >[EMAIL PROTECTED] >subsidiaries of small independent publishing co. >[EMAIL PROTECTED] >[EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php