MySQL cannot find the username in its grant tables.
The error message very clearly states that there is no user named
'x,@host' which is the value of your $user variable. For your example,
$email == 'x' and $femail == '@host'. The comma is included because it
is part of the literal string, i.e., inside the double quotes.
On Tue, 14 Jan 2003 22:08:11 -0600, Addison Ellis wrote:
> do you have any idea why the following(line 106)would return
>error message ? the login.php has an included form to create an
>account and that is what will not connect.
>$connection = mysql_connect($host, $user,$password) //this is line 106
>Warning: Access denied for user: 'x,@host' (Using password: YES) in
>/users/infoserv/web/register/login.php on line 106
>Warning: MySQL Connection Failed: Access denied for user: 'x,@host'
>(Using password: YES) in /users/infoserv/web/register/login.php on
>Couldn't connect to server.
>my required file is as follows:
>thank you again for your time. addison
>small independent publishing co.
>114 B 29th Avenue North
>Nashville, TN 37203
>subsidiaries of small independent publishing co.
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