Try "SELECT id,LEFT(fluff,80) as fluffy FROM sometable"
Then extract() will have a value for fluffy
--- Baumgartner Jeffrey <[EMAIL PROTECTED]> wrote:
> I'm having a problem when I use mysql_fetch_array and extract()
> following a
> left select query. As an example...
>
> $query = "SELECT id,LEFT(fluff,80) FROM sometable";
> $result = mysql_query($query) or die('message');
>
> while ($row = mysql_fetch_array($result){
> extract($row);
> echo "<P>" . $id . ": " . $fluff . "</P>";
> }
>
> would echo the $id, but there would be nothing for $fluff. However,
> if I
> select only 'fluff' from the MySQL table, I get the full text for
> $fluff. I
> am reluctant to SELECT the entire fluff text from the table and
> shorten it
> in PHP as that seems inefficient to me - (but correct me if I am
> wrong).
>
> I expect the solution must be dead easy, but I can't find it or
> figure it
> out.
>
> Many thanks,
>
> Jeffrey
>
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>
=====
Mark Weinstock
[EMAIL PROTECTED]
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