You haven't thorougly read my message, about 4/5 lines down i have said "(yes it is included in a script that connects to the database i am using)"
:)
i have another script that calls this function script, and at the top of it, it calls a script that contains my connection information.


I have tested it with other queries that work... and there is no problem, i am definately connected to the database





From: Koleszár Tibor <[EMAIL PROTECTED]>
To: "David Rice" <[EMAIL PROTECTED]>
Subject: Re: [PHP-DB] need help with fetching a result using a function
Date: Sun, 2 Mar 2003 16:54:25 +0100

Hello,

You have forgotten to connect :)
This error occurs when the $result variable is false and it is not
a resource (database query) id.

Tibor

PS:
for any db:
 $conn_id = connect(...);
 $result_id = query($conn_id, ....);
 $row = fetch($result_id);

...



----- Original Message -----
From: "David Rice" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, March 02, 2003 4:49 PM
Subject: [PHP-DB] need help with fetching a result using a function


>
> I am trying to write a few functions for a project i need to do for
school,
> this function should return all the inactive, or active users (1 or 0
> staffstatusid) as an array for creating a drop down menu.
>
> Now when i perform the following code (yes it is included in a script that
> connects to the database i am using) it returns the following error.
>
> "Warning: Supplied argument is not a valid MySQL result resource in
> /home/filterseveuk/public_html/project/getusers.php on line 7"
>
> and underneath the error it prints the value of var_dump($data)
> which is " NULL"
>
> any ideas how to fix this?
>
>
> =================================================================
> <?
> function getusers($status){
>
> $query = "SELECT FROM Staff WHERE Staffstatusid = '$status'";
> $result = mysql_query($query);
> $row = mysql_fetch_array($result);
> $users[$status] = $row ;
> return $users[$status] ;
> }
> $status = 0 ;
> $data = getusers($status);
> var_dump($data);
>
> echo $data;
> ?>
>
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