$tips[0] = "value"; $tips[1] = "value"; $tips[2] = "value";
Although, if you REALLY want dynamic variable names.
$i = 1; $varname = 'tips_'.$i; $$varname = "value";
this will make a variable like below:
$tips_1 = "value";
But like I said before, it's better to use arrays - they are much more flexible (and PHP arrays are especially cool).
http://www.php.net/manual/en/ref.array.php
adam
Just a quick question about dynamic variables
would like to end up with a variable called $tips_1 $tips_2 ... $tips_n
where "n" is the value of the variable $sid
i have tried
$tips . '$sid';
and other variants, but i can't get one that doesn't return a parse error or T_VARIABLE error.
-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
