Hmm... that is not quite it. Here is a better example:

Here is how I would define default values for a checkbox in HTML_QuickForm;

$defaultValues['ichkABC']   = array('A'=>true,'B'=>true);
$form->setDefaults($defaultValues);

The checkboxes are defined later like this:

$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'A', null, 'A');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'B', null, 'B');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'C', null, 'C');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'D', null, 'D');
$form->addGroup($checkbox, 'ichkABC', 'ABCD:', array('&nbsp;', '<br />'));


So what I am trying to do is built that array that gets passed to: $defaultValues['ichkABC'] =

If I can create a variable that contains the array that is fine too. the values 'A' or 'B' as in the above example will be the values in quotes as I get them from my table query.


thanks charles



On Monday, March 31, 2003, at 04:52 PM, Jennifer Goodie wrote:

$mystring;
foreach ($sth_opt as $thekey => $thevalue){
        $mystring .= "'".$thevalue."'=>true, ";
}
$defaultValues['ib_article']   = array($mystring);

Try this ...


foreach ($sth_opt as $thekey => $thevalue){
        $defaultValues['ib_article'][$thevalue] = 'true';
}

I'm not sure if the indices line up exactly with what you had in mind, but
I'm confident you can play with it to get what you want.



-----Original Message----- From: Charles Kline [mailto:[EMAIL PROTECTED] Sent: Monday, March 31, 2003 1:49 PM To: Jennifer Goodie Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] using a variable as values in an array


Here is more details. Thanks for the reply.


I am using HTML_QuickForm (pear) to create my forms. In order to set
the default state of some of the elements (checkboxes in this case) I
need to pass an array as the value to QuickForm.

This array needs to be in the format of this:

array('30'=>true, '29'=>true) where the 30 and 29 are the values that
are coming back from my query. This could return up to 50 records.

This is what I was trying, but it isn't woring:

$mystring;
foreach ($sth_opt as $thekey => $thevalue){
        $mystring .= "'".$thevalue."'=>true, ";
}


On Monday, March 31, 2003, at 04:32 PM, Jennifer Goodie wrote:


Instead of building a string in your loop do the assignment in the loop
I have no idea what is being pulled from where, so I can't really give
a
good example


-----Original Message-----
From: Charles Kline [mailto:[EMAIL PROTECTED]
Sent: Monday, March 31, 2003 1:25 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] using a variable as values in an array


I am trying to build an array from the results of a query on a mySQL table.

I am using a loop to create this string in a variable $mystring:

'30'=>true, '20'=>true

I then need to use it like this:

$defaultValues['ib_article'] = array($mystring);

It isn't working. I am sure there is a better method, can anyone point
me in the right direction?

thanks
charles


-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php


-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php



--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Reply via email to