form feeds don't work in html. It is interpreted as a space.

Arthur Chevalier wrote:
Hello,
I am having problems getting the \f (form feed) expression to work. After a
certain amount of lines print I want to start printing the next line on a
new sheet of paper. Any ideas of what I could be doing wrong. Below is a
sample piece of my code. The bold code is where I am trying to issue the
form feed.
while($row = mysql_fetch_array($dbResult))
{
print("<TR>\n");
print("<TD class=\"tdborder\"><A
HREF=\"show_single_server.php?server_name=$row[0]\" TARGET=\"text_float\">"
. $row[0] . "</TD>\n");
print("<TD class=\"tdborder\">". $row[1] . "</TD>\n");
print("<TD class=\"tdborder\">". $row[2] . "</TD>\n"); print("<TD class=\"tdborder\"><A
HREF=\"$PHP_SELF?mid_tier=$row[3]&db_rel=0\" TARGET=\"text_float\">".
$row[3] . "</TD>\n");
print("<TD class=\"tdborder\"><A
HREF=\"$PHP_SELF?db_rel=$row[4]&mid_tier=0\" TARGET=\"text_float\">".
$row[4] . "</TD>\n");
$rowdata = $row[5];
if($rowdata == "")
{
print("<TD class=\"tdborder\">&nbsp;</TD>\n");
}
else
{ print("<TD class=\"tdborder\">". $row[5] . "</TD>\n");
}
print("<TD class=\"tdborder\">". $row[6] . "</TD>\n");
//print("</TR>\n");
if($counter == "20")
{
$counter = "0";
print("</TR>\f");
continue;
}
else
{
$counter ++;
print("</TR>");
continue;
}
}




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