hmmm,
maybe this code..
$info->load("/".$dir.$file);
if $dir = mp3s and $file = test.mp3
then it will load '/mp3s/test.mp3'
you got that directory?
I've seen the class and you are hiding the fopen error message, which could be
the problem.
.: Allowee
On Saturday 07 June 2003 11:11, Ole Hornauer wrote:
> hi allowee,
>
> sorry, this was not meant to be. $info2 is supposed to be $info. my
> fault. but that is not the actual problem.
>
> > Hi,
> >
> > Where do you get $info2 from?
> > I only see $info in this function.
> >
> > .: Allowee
> >
> > > function scan_dir($dir)
> > > {
> > > $info = New mphp3(2);
> > >
> > > $handle = @opendir($dir);
> > > while ($file = @readdir ($handle))
> > > {
> > > if (eregi("^\.{1,2}$",$file))
> > > {
> > > continue;
> > > }
> > >
> > > if(is_dir($dir.$file))
> > > {
> > > scan_dir($dir.$file."/");
> > > }
> > > else
> > > {
> > > $info->load("/".$dir.$file);
> > >
> > > $query ="insert into mp3 (
> > > file,
> > > path,
> > > artist,
> > > title,
> > > album)
> > > values (
> > > '$info2->filename',
> > > '$dir',
> > > '$info2->v2_artist',
> > > '$info2->v2_title',
> > > '$info2->v2_album');";
> > >
> > > mysql_query($query);
> > > }
> > > }
> > > @closedir($handle);
> > > }
> > > scan_dir("mp3/");
> > > ?>
> > >
> > > but all it does is to put the path ($dir) into the database. everything
> > > else is ignored. an error does not occur. since the simple demo works
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