maybe try the invers (anyways you havn't defined an action-attribute - maybe this is a problem?):

if(!isset($_SESSION['item_details']) || ( isset($_SESSION['item_details'] && $_SESSION['item_details']) {
echo '<form name="myForm" method="post" action="'.basename($_SERVER['PHP_SELF']).'">'.
'<input name="view_details" type="hidden" value="yes">'.
'<input type="submit" value="View Descriptions">'.
$_SESSION['item_details'] = 'yes';

hope i understood you right and this helps?


w: http://www.abendstille.at

# life would be easier if i knew the source code

Am Montag, 16.06.03 um 17:16 Uhr schrieb Becoming Digital:

Despite my best efforts, I can't seem to set session variables via a basic form.
I'm trying to use a button to alter display settings, which should be a simple
task, but apparently it is not. Here's the code I'm working with.

if( (!isset( $_POST['view_details'] )) && ($_SESSION['item_details'] != "yes") )
print "<form method=\"post\">";
print "<input type=\"button\" name=\"view_details\" value=\"View
Descriptions\" />";
print "</form>";
$_SESSION['item_details'] = "yes";

My session I have tried a number of different solutions, including removing
session_start() from its calling function and various things I might otherwise
overlook. I'm sure that I'm overlooking something easy but I can't figure out
what it is. The session variable simply isn't being set, as confirmed by
printing its value (and by things not working!). Thanks a lot for any and all

Edward Dudlik
Becoming Digital

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