Yup, I have all permissions -- it appears that I can access mysql but not the database itself.
"Gary Every" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] . > Do you have select permissions on that DB/table? > > If you have GRANT permissions, try > GRANS SELECT, INSERT, UPDATE, DELETE ON db.tablename to > 'youruser'@'your.ip.address' IDENTIFIED BY 'yourpassword'; > > your.ip.address can be substituted with localhost if you're on the same box. > > > Gary Every > Sr. UNIX Administrator > Ingram Entertainment > (615) 287-4876 > "Pay It Forward" > mailto:[EMAIL PROTECTED] > http://accessingram.com > > > > -----Original Message----- > > From: Greg Hetrick [mailto:[EMAIL PROTECTED] > > Sent: Wednesday, July 09, 2003 12:31 PM > > To: [EMAIL PROTECTED] > > Subject: Re: [PHP-DB] mysql_fetch_array issues. > > > > > > I do not have the die statment -- the DB is the same except > > the name and I > > have double checked that I just did a back up of the previous > > db and moved > > it to the new server. I have done some more digging, my query > > appears to > > work, but I almost appears that I have a problem with selecting the > > database -- > > if I comment out the mysql_select -- statment I get the same > > error, perhaps > > I just can't get to that DB. > > intresting. > > > > I guess I can assume at this point there is something flaky with my DB > > > > > > "Jeffrey N Dyke" <[EMAIL PROTECTED]> wrote in message > > news:[EMAIL PROTECTED] > > > > > > Do you have an 'or die(mysql_error())' statement following your > > > mysql_query($result) line. 99% of the time, this error > > means your query > > > failed. if it works on another server....are the fields > > the same, the > > > dbname, the tablename? > > > > > > hth > > > jeff > > > > > > > > > > > > "Greg Hetrick" > > > <[EMAIL PROTECTED] To: > > [EMAIL PROTECTED] > > > net> cc: > > > Subject: [PHP-DB] > > mysql_fetch_array issues. > > > 07/09/2003 12:04 > > > PM > > > > > > > > > > > > > > > > > > > > > I am getting the following error when attempting to pull > > data out of a > > > mysql > > > DB > > > > > > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL > > result > > > resource in > > /home/pffl/public_html/pffl/webpage/html/dataentry.php on line > > > 125 > > > > > > I can take this same code to a different web server and it > > is pulling > > > correctly! > > > > > > I am currently running Apache 2.0.46 with PHP 4.3.2 I was > > running Apache > > > 1.3.x with PHP 4.3.1 and getting the same thing, any ideas? > > here is the > > > chunk of code where I use the function. > > > > > > while ($myrow=mysql_fetch_array($result)) > > > { > > > ?> > > > <option value="<?print $myrow['name'];?>, <?print > > > $myrow['team'];?>"> <? echo $myrow["name"]; ?></option> > > > <? > > > } > > > > > > Any Ideas. > > > > > > > > > > > > -- > > > PHP Database Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > > > > > > > > > > > > > > > -- > > PHP Database Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
