> How do you pass by reference? I tried
> $var = myFunction(&$var1, &$var2);
> but it gave me a warning saying that pass by reference is depreciated

Call time pass by refrence is depreciated you should read the manual to see
how it should be done.

PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to