The date() is for use with the 32-bit C time value returned by functions
like time(). Data from fields of type datetime are returned as strings in
the form Jan 9 2004 by the mssql extension as the default. To return it
using ISO format set mssql.datetimeconvert to "On" in the php.ini file, or
use the following command:
ini_set('mssql.datetimeconvert' , 1 );
-- bob
On Mon, 26 Jan 2004, Steve wrote:
> I have Apache 1.3 and PHP 4 running on Windows 98 connecting to a local
> MS SQL 7.0 server. MS SQL has the date as 2004-01-09 (YYYY-MM-DD), when
> I print the date to a webpage with this PHP code:
>
> printf("Date Picked Up: %s\nDate", date("Y/j/n",$row[0]);
>
> I get this output:
>
> 1969/12/31
>
> What is wrong?
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
