Hello,
I'm a php beginner and not succeed in fetching an oracle query result into an array. I want to load the colum names of a table (from an Oracle9i) into a <select>-field. There is something working, but only the last column name appears in the select field and is wraped by each letter.
For instense acw_fid_lab:
___
|non|
|all|
|A |
|C |
.
. and so on.


What are my mistakes? If anyone could suggest me how to solve it or using a better approach...

Thank you, Torsten
---------------------------------------------------
My last version (I also tried OCIFetchInto before):
---------------------------------------------------
function fill_select($table_name)
   {
   $connect = @OCILogon("", "", "");

if(!$connect)
{
$err_oci = OCIError();
echo "(2) No connection - OCIError(): &nbsp;&nbsp;&nbsp;".$err_oci["message"];
echo "<p>";
}
else
{
$sql_table_names = "SELECT column_name FROM user_tab_columns
WHERE table_name = '".$table_name."'";
$stmt = OCIParse($connect, $sql_table_names);
OCIExecute($stmt);


         $column_name = array();
         $counter = 0;

         while(OCIFetch($stmt))
            {
            $column_name = OCIResult($stmt,'COLUMN_NAME');
            $counter++;
            }

         if($counter == 0)
            {
            $column_name[0] = "nothing found";
            }
         OCIFreeStatement($stmt);
         OCILogOff($connect);
         return($column_name);

         }
   }

# This is a cut-out from that file I call the function from
echo "   <td>\n";
echo "       <select name=\"chemistry\" size=\"12\" multiple>\n";
echo "       <option>none</option>\n";
echo "       <option>all</option>\n";
             $table_name = "AN_CHEMISTRY_WATER";
             $count = (int) count_table_columns($table_name);
             $column_names = fill_select($table_name);
             for($i=1; $i<=$count; $i++)
                {
                echo "<option>",$column_names[$i],"</option>\n";
                }
echo "       </select>\n";
echo "   </td>\n";

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