On Thursday 26 February 2004 01:04, PHELPS, SCOTT wrote:

> The problem is that it only prints one name.  Also next() doesn't seem to
> be advancing the table so I am getting duplicates of the one name it does
> print to the table

For starters, you're using next() incorrectly. It returns a value.

Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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