I checked em all they were right "Daniel Clark" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Sounds like it doesn't like your SQL statement. Perhaps a field or table > name is incorrect? > > > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL > > result > > resource in ....... > > "Daniel Clark" <[EMAIL PROTECTED]> wrote in message > > news:[EMAIL PROTECTED] > >> What error are you getting? > >> > >> > why doesn't this work: > >> > $pic=mysql_query('SELECT Rune, username FROM RuneRunner > >> > RuneRunner_1 WHERE (User_ID = 3)',$connection); > >> > $pic=mysql_fetch_array($pic);
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