"John W. Holmes" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> [EMAIL PROTECTED] wrote:
> > Would somebody be kind enough to explain why this query produces a false
result
> >
> > $latest=mysql_query("SELECT MAX(fee_recd) FROM members",$connectup)or
die
> > ("Query failed:<br>$latest<br>Error: " . mysql_error());
>
> Would you be kind enough to tell us what text mysql_error() shows?
>
> You probably just need to use an alias in your query:
>
> SELECT MAX(fee_recd) AS max_fee_recd FROM members
>
> and then you'll have $row['max_fee_recd'] when you fetch the value from
> your result set. Other wise you need to use $row['MAX(fee_recd)']...
I did reply but it seems to have gone astray.
Thanks. There no report from error() and obviously the result of the query
is not false. I was trying to solve the wrong problem which was in the PHP
statement that followed. Using your example, this was successful
$latest=mysql_query("SELECT MAX(fee_recd) FROM members",$connectup)or die
("Query failed:<br>$latest<br>Error: " . mysql_error());
while ($myrow= mysql_fetch_array($latest)){
$recentpaid=$myrow['MAX(fee_recd)'];
}
Louise
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