You can use something like $articleDate= date ("Y-m-d 00:00:00",strtotime($day ." " . $month . " " . $year));
If $day = 10 and $month = "January" and $year = 2004 then $articleDate will be set to "2004-01-10 00:00:00" Then you can insert $articleDate into a datetime field in mysql. "Irm Jr" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] Hi all, currently I have a form which prompts for the user to choose a date. The dropdown lists are stored into variables: $month //e.g. January, February, ... $day //e.g 1 - 31 $year //e.g. 2004 (four digits) then combined into $articleDate How can I manipulate this variable to be in such a format that I can insert the information into a DATE column in a mySQL database. Dates are a bit of a mystery to me as PHP and MySQL handle them differently. Your help is appreciated. Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php