On Fri, 6 Aug 2004 10:21:19 +1000, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> Thanks Eric,
> 
> I have changed it somewhat but am just getting a parse error,
> unexpected T_STRING on that line.
> 
> My revised code is below:
> 
> 
> print "<b>Current Staff Working Alone</b>";
> print "</td></tr>";
> print "</table>\n";
> print "<table border=\"1\" cellpadding=\"3\" cellspacing=\"0\">\n";
> print
> "<tr><td></td><td><b>Name</b></td><td><b>Location</b></td><td><b>Time
> in</b></td><td><b>Time Out</b></td>/tr>";
> while ($row = mysql_fetch_array($result, MYSQL_BOTH))
> {
>     print "<tr><td>";
>     print "<INPUT TYPE='RADIO' NAME='id' VALUE='".$row["id"]."'>";
>     print "</td><td>";
>     print $row["name"];
>     print "</td><td>";
>     print $row["location"];
>     print "</td><td>";
>     print $row["timein"];
>     print "</td><td>";
>     if ($row["timeout"] IS NULL);
>     {
>     print <input name="timeout" type="text" value="echo date('H:i')">;
>     } else {
>     print $row["timeout"];
>     }
>     print "</td></tr>\n";
>     }
>     print "</table>\n";
> 
> <input type="submit" name="submit2" value="Select your name and click
> here to record your timeout"></form>
> 
> 
> 
> 
> -----Original Message-----
> From: Eric Schwartz [mailto:[EMAIL PROTECTED]
> Sent: Friday, 6 August 2004 9:31 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] Php if statement in a form
> 
> On Fri, 6 Aug 2004 08:53:53 +1000, [EMAIL PROTECTED]
> <[EMAIL PROTECTED]> wrote:
> > Hello, I wonder if someone could point me in the right direction here.
> >
> > I have a table that is displayed that is also a form, and allowed a
> > person to select a record to update using a radio button. With one of
> > the fields of the form/table however, I would like it to display the
> > value in the db (if there is one). If there is no value then I want
> the
> > field to display the current time and then submit it to the db as a
> > variable.
> >
> > I can get it to display the current time and submit it to the db, but
> I
> > don't know how to do the IF bit of the form/table.
> >
> > Anyway, the code is below.
> > Thanks
> >
> > <?
> > $dbcnx = @mysql_connect( "localhost", "user", "password");
> > mysql_select_db("movements");
> > $result = mysql_query("SELECT id, name, location, timein, timeout FROM
> > workalone WHERE date=CURRENT_DATE()") or die (mysql_error());
> > // Display the results of the query in a table
> > print "<b>Current Staff Working Alone</b>";
> > //below is the table/form with the id, name, location, timein and
> > timeout taken from the db
> > print "<table border=\"1\" cellpadding=\"3\" cellspacing=\"0\">\n";
> > print
> > "<tr><td></td><td><b>Name</b></td><td><b>Location</b></td><td><b>Time
> > in</b></td><td><b>Time Out</b></td>/tr>";
> > while ($row = mysql_fetch_array($result, MYSQL_BOTH))
> > {
> >     print "<tr><td>";
> >     print "<INPUT TYPE='RADIO' NAME='id' VALUE='".$row["id"]."'>";
> >     print "</td><td>";
> >     print $row["name"];
> >     print "</td><td>";
> >     print $row["location"];
> >     print "</td><td>";
> >     print $row["timein"];
> >     print "</td><td>";
> > //below is the IF thing I am having problems with
> >     ?><input name="timeout" type="text" value="if {$timeout=null <?php
> > echo date('H:i');?>} else {<?print $row["timeout"];?>"><?
> >     print "</td></tr>\n";
> > }
> > print "</table>\n";
> >
> > ?><input type="submit" name="submit2" value="Select your name and
> click
> > here to record your timeout"></form>   <?
> >
> > if ($submit2)
> > {
> > $dbcnx = @mysql_connect( "localhost", "user", "password");
> > mysql_select_db("movements");
> > $result = mysql_query("UPDATE workalone SET timeout='$timeout' WHERE
> > id='$id'") or die (mysql_error());
> > echo "<b>Thank you, your Time Out has been recorded.</b>";
> >
> > --
> > PHP Database Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
> 
> You seem to have your php tags not around your if statement and you
> are checking to see if $timeout rather than $row["timeout"] has a
> value.  I also think the proper way to check for NULL is to say IS
> NULL or NOT NULL, not $foo = NULL.  Could be wrong about that one.
> 
> <?php
> if ($row["timeout"] IS NULL) {
>  echo date('H:i');
> } else {
> print $row["timeout"];
> }
> ?>
> 
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> 
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> 
> 

Try adding a quote on the line and escaping the other quotes, like this:

print "<input name=\"timeout\" type=\"text\" value=\"".echo date('H:i')."\">";

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