$val="127.0.0.1";
$query="INSERT INTO node set uri=\"$val\", name=\"bla\"";
Try this one... think is better n less confusing for u...
On Sun, 19 Sep 2004 19:13:48 +0200, Darryl <[EMAIL PROTECTED]> wrote:
>
> $val = "127.0.0.1";
> $query = "INSERT INTO node (uri,name) VALUES ('".$val."','bla')";
>
> Try that?
>
>
> -----Original Message-----
> From: Stefan Reimers [mailto:[EMAIL PROTECTED]
> Sent: Sunday, September 19, 2004 6:37 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] SQLite problem INSERTing string
>
> Hello,
>
> I am currently experiencing a problem with an INSERT statement in SQLite.
>
> First of all an excerpt from the code:
>
> $val = "127.0.0.1";
> $query = "INSERT INTO node (uri,name) VALUES (".$val.",'bla')";
>
> $db_name = "mysqlite";
>
> if($db_hdl = sqlite_open($db_name)){
>
> $db_result = sqlite_query($db_hdl,$query);
>
> }
>
> I get the error message:
>
> Warning: sqlite_query(): near ".": syntax error in
> C:\Programme\xampp\htdocs\dipl\testclient\sqlite_test.php on line 10
>
> I tried addslashes (which I know I shouldn't), sqlite_escape_string, any
> variant of quotes etc, I asked google and the searched the news groups
> but with no relevant result, except the insight, that others experience
> the same so long unsolved problem or use a syntax in their tutorials
> that does not work with my code...
>
> As you an see from the error message, I use Windows, Apache, PHP4 with
> SQLite in a 2.8.14 version.
>
> If anyone has a clue, please contact me or just answer.
> Thanks in advance
> Stefan
>
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