bastien
From: Karen Resplendo <[EMAIL PROTECTED]> To: [EMAIL PROTECTED] Subject: [PHP-DB] Why does this conditional run, even if not true? Date: Fri, 8 Oct 2004 18:33:02 -0700 (PDT)
$c is a field in an array I have loaded in from a text file. For some reason, none of the conditionals branch off and I end up printing out error messages for every row in the text file. My brackets are balanced, I just didn't include the bottom part:
If ($c==9) { If($fieldarray[3]=="P") {
$reject=validate($fieldarray[0],$c,$connectionSDWIS, $fieldarray[$c],$c);
This If statement runs even if $reject = "YES". Can't figure out why:
if ($reject=="NO")
{
//////////////////////////////////////////////////////////////////////////////////////////////////
//loop through the rows in the this text file checking for Original ID of Repeat
//////////////////////////////////////////////////////////////////////////////////////////////////
$handle2 = fopen ($uploadfileandpath,"r");
while ($field2array = fgetcsv ($handle2, $userfile_size, ","))
{
If($field2array[2]!=$fieldarray[$c])
{
echo "<br>Field 2 of array 2 text row: ".$field2array[2]."<br>";
echo "<br>Field 9 of array 1 text row: ".$fieldarray[$c]."<br>";
$acceptOrReject = "R";
$displayrows.="<font color=red><b>See below: Original Sample ID for Repeat does not exist : ".$fieldarray[$c]."</b></font><br>";
}
} //end of while loop
fclose($handle2);
}//end of If($reject =="No")
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