On Tuesday 09 November 2004 19:12, Aaron Todd wrote:
Please do not top post (google > top post).
> I tried the double quotes but that didn't seem to matter.
It does matter.
> I also put the
> command string in a variable and then am running the variable with exec.
> Still it doesnt work.
Splitting it up into 2 steps is to aid in debugging.
> $filename = "/home/virtual/site341/fst/var/www/html/db_backup_" .
> date("n-j-y").".sql";
> $command = "/home/virtual/site341/fst/usr/bin/mysqldump -u ***** -p*****
> database > $filename";
> echo $command;
If what is being echoed looks OK then
> exec($command);
make use of the extra arguments to exec() (see manual) so that you can see
what's being output.
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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