try this:

$sql = "SELECT * FROM cm_customer WHERE
emial='$user'";

$sql_query = mysql_query($sql) or die($mysql_error());

bastien


From: "Henrik Hornemann" <[EMAIL PROTECTED]>
To: <php-db@lists.php.net>
Subject: SV: [PHP-DB] i am lost (php warning)
Date: Tue, 18 Jan 2005 09:15:01 +0100

Hi,

Probably because $user is not in the database.

Regards Henrik Hornemann

-----Oprindelig meddelelse-----
Fra: Earl Clare [mailto:[EMAIL PROTECTED]
Sendt: 18. januar 2005 07:59
Til: php-db@lists.php.net
Emne: [PHP-DB] i am lost (php warning)
Prioritet: Høj

Hi ya'll,



I am lost as to why I am getting this error in my script. Can anyone kindly explain why this is so.



Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/cm/public_html/cell/login.php



----------------------------------------------------------------------------
---

                              My script

----------------------------------------------------------------------------
---





if($_POST['submit'] == '>Log In')

{

            $user=$_POST["email"];

            $pass=$_POST["pass"];

$sql_query = mysql_query("SELECT * FROM cm_customer WHERE emial='$user'");

            $sql_query = mysql_num_rows($sql_query);



            if (($sql_query) >0)

{

                                    $valid = $user;

                                    session_start();

                                    session_register("valid");

}

}



  if (session_is_registered("reg"))

  {

              echo "ok";

  }



  else

  {

     echo "sorry";

  }



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