Ron Piggott wrote:
That strtotime is a neat little command. With a bit more searching I found
that this works:
$expiry_date = strtotime("+21 days");
$expiry_date = date('Y-m-d', $expiry_date);
echo $expiry_date;
The computer couldn't cope with me doing it in just one line --- I got a
parse error.
the computer coped when I did it on oneline, maybe you had a typo or
something:
echo date("Y-m-d", strtotime("+21 days"));
sidenote: I use doublequotes here because its easier when testing in a linux
shell....but unless you need string interpolation its better to use single
quotes for your strings.
Ron
----- Original Message -----
From: Calvin Lough <[EMAIL PROTECTED]>
To: Ron Piggott <[EMAIL PROTECTED]>; PHP DB <php-db@lists.php.net>
Sent: Wednesday, March 02, 2005 10:50 AM
Subject: Re: [PHP-DB] Expiry Date ($date function)
The strtotime function should work the best.
$add_twentyone = strtotime("+21 days");
I dont know if that will work or not. I just found that method in the
php doc and it looked interesting. Hopefully it will work for you.
Calvin
On Wed, 2 Mar 2005 04:41:04 -0500, Ron Piggott
<[EMAIL PROTECTED]> wrote:
I figured out that the syntax below creates the date in the way it may
be
stored in a mySQL table:
$todays_date=DATE('Y-m-d');
Is there any way to add 21 days to this as an expiry date? For example
if
the date was March 20th 2005 21 days would be in April --- is there any
way
of dealing with this?
Ron
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