"echo ${$VarName}['second'];
is what you want - you want to be very clear what order these things
need to be analyzed in, especially when dealing with arrays and the
likes."
That was the problem!!! Thanks guys.
<>< Ryan
-----Original Message-----
From: Martin Norland [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 10, 2005 12:19 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Variable Variable Array
Ryan Jameson (USA) wrote:
> Hi Folks,
>
> I've been using "variable variables" for years with PHP.
>
> $var = "myVarName";
> $$var = "Some Val";
>
> echo $myVarName; //outputs "Some Val"
[snip]
> Example:
>
> $var['first']='bob';
> $var['second']='frank';
>
> $varName = "myVarName";
> $$varName = $var;
>
> echo $$varName['second']; //should output "frank" but doesn't. :-\
> <-----------------------------
> echo $var['second']; //should output "frank" works fine.
Try adding
$frank = 'woopsie!';
to the top of your script and running it.
-----
echo ${$VarName}['second'];
is what you want - you want to be very clear what order these things
need to be analyzed in, especially when dealing with arrays and the
likes.
Cheers,
--
- Martin Norland, Sys Admin / Database / Web Developer, International
Outreach x3257 The opinion(s) contained within this email do not
necessarily represent those of St. Jude Children's Research Hospital.
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