Hi !

Could you do a "print_r($result)" after your mysql_query ?

Or you sure of your argv[1] ?

Sylvain Gourvil

Evert Meulie wrote:
Hi all!

I'm taking my first steps with PHP & MySQL.

Can anyone give me a hint on why this would not work?


$result = mysql_query('SELECT SUM(AcctInputOctets), SUM(AcctOutputOctets) FROM radacct WHERE username = $argv[1] ');
echo mysql_result($result,0), "\n";
echo mysql_result($result,0,1);


I get: Warning: mysql_result(): supplied argument is not a valid MySQL result resource


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