Hi,
Well I tried this code but it fails, if I enter a correct User and Pass set in
the db it just prompts for the user/pass again. The error message that should
apply if wrong three times appears but the sucessful message I can't get
regardless of correct user pass or not, any help please?
<?php
function displayLogin() {
header("WWW-Authenticate: Basic realm=\"My Website\"");
header("HTTP/1.0 401 Unauthorized");
echo "<h2>Authentication Failure</h2>";
echo "The username and password provided did not work. Please reload this page
and try again.";
exit;
}
$db = mysql_connect('localhost','db_user',db_pass') or die("Couldn't connect to
the database.");
mysql_select_db('db_name') or die("Couldn't select the database");
if (!isset($PHP_AUTH_USER) || !isset($PHP_AUTH_PW)) {
// If username or password hasn't been set, display the login request.
displayLogin();
} else {
// Escape both the password and username string to prevent users from inserting
bogus data.
$PHP_AUTH_USER = addslashes($PHP_AUTH_USER);
$PHP_AUTH_PW = md5($PHP_AUTH_PW);
// Check username and password agains the database.
$result = mysql_query("SELECT count(id) FROM users WHERE
password='$PHP_AUTH_PW' AND username='$PHP_AUTH_USER'") or die("Couldn't query
the user-database.");
$num = mysql_result($result, 0);
if (!$num) {
// If there were no matching users, show the login
displayLogin();
}
}
// All code/html below will only be displayed to authenticated users.
echo "Congratulations! You're now authenticated.";
?>
J
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