I am getting link from visitor using form, that means I don't have control what they would type. e.g they may type http://www.suggestedlink.com/myfav.wav, www.suggestedlink.com/myfav.ram and http://suggestedlink.com/myfav.mp3 or so I am looking general version which can handle all.
and on top of that I wanted to play music file in to the default player, but it did not work. I used something like this. select music_file from music where id=\"$id\" $temp = $result <src=\"$temp\"> so everything is working fine except I got file not found, and the file path is something like this http://www.mydomain.com/www.suggestedlink/myfav.mp3 so what should I do. On 12/7/05, Edward Gray <[EMAIL PROTECTED]> wrote: > > actually, you may want to check the source of the page. if the url does > not start with "http://" (or https, or ftp, etc.), browsers will assume the > link is on the current server. how are you storing the urls? as full urls, > as domain/path/file.htm, ....? if all of your urls should start with > "http://", you could either store them in the database that way or > echo 'http://' . $temp; > > hope this helps. > > > Edward Gray > Web Development Team > University of Mary Washington > 540-654-1564 > > >>> "Bastien Koert" <[EMAIL PROTECTED]> 12/06/05 1:44 PM >>> > $url = str_replace("www.mydomain.com","",$url) > > bastien > > > >From: Mohamed Yusuf <[EMAIL PROTECTED]> > >To: email@example.com > >Subject: [PHP-DB] problem of retrieving urls from mysql > >Date: Tue, 6 Dec 2005 09:51:18 -0800 > > > >I would like to store and retrieve urls, but I have problem which is I > get > >my url + the other url, Instead I should get another url only > > > >$temp = linkurl; > >echo "$temp"; > > > >the echo prints something like this > >http://www.mydomain.com/www.otherlink.com > > > >so I wan get rid off my url and get only other link, so how can I do > that? > > > >thanks in advance > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >