u can have the query as
$query = " select * from $table where nameId = 31 " ;
$result = mysql_query ( $query ) ;
$i = 0 ;
while ( $row = mysql_fetch_array( $result , MYSQL_NUM ) )
{
$array[$i][0] = $row[0] ;
$array[$i][1] = $row[1] ;
$array[$i][2] = $row[2] ;
$i++
}
// now $array has ur required names :-)
rajesh
On Sat, 14 Jan 2006, Sjef Janssen wrote:
Hi there,
I have a table that keeps names for different language codes.
In a short example:
nameId name languageCode
31 House EN
31 Wohnung DE
32 Piece En
32 Stuck De
33 Car EN
33 PKW DE
What I would like is to have a query that returns for example:
nameId = 31
Names = House - Wohnung
Maybe I can even have a result that consists of an array with nameIds and
Names.
Or should I fire a bunch of queries after each other to have this result?
I use mysql and php 4.3.8
Tnxs!!
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