this regex isn't perfect at all but might do the job. You should
modify the pattern to match the year part against 2037 as a maximum
and also don't forget to checkdate().


    $date = '30/03/2983 12:00';
    $pattern = '[0-3][0-9]/[0|1][0-9]/[1|2][0-9]{3,3}\s[0-2][0-9]:[0-5][0-9]';
    if (preg_match("!^$pattern$!", $date) === 1) {
        echo 'date is in valid form';
    else {
        echo 'date form is invalid';


Hope it helps,


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