$cols = 2;
echo "<table><tr>";
while ($rows = mysql_fetch_array($result))
{
if (($cols % 2) == 0 ){ echo "</tr><tr>"; }
echo "<td>".$rows['something']."</td>";
$c++;
}
echo "</tr></table>";
bastien
From: Mark Bomgardner <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED]
To: Php-Db <php-db@lists.php.net>
Subject: [PHP-DB] Result set in different columns
Date: Mon, 10 Apr 2006 09:00:06 -0500
I am trying to work through some display logic where I want to display a
results set from a database query into to columns in a table, but I can't
see to get it correct.
Example; I want to loop through the months of the year and display them
like this;
January February
March April
May June
July August
September October
November December
Any ideas?
Mark Bomgardner
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